ICSE 2023 Computer Applications Question Paper for Class 10

About this paper

This is the official ICSE Class 10 Computer Applications paper for the 2023 examination, paper code T23 861. It carries 100 marks and allows two hours of writing after fifteen minutes of reading time. Section A (40 marks) is compulsory: Question 1 has twenty one-mark multiple-choice items on Java concepts, and Question 2 has ten two-mark parts on expressions, loop conversion, Character and String methods, arrays and output prediction. In Section B candidates write Java programs for any four of six questions: a Student stream-allocation class, bubble sort of characters, overloading print() with a lead-number check, counting digits, letters and special characters, linear search, and summing one- and two-digit numbers. This copy has the questions only.

Exam

ICSE Class 10

Subject

Computer Applications

Year

2023

Paper code

T23 861

Maximum marks

100

Time allowed

2 hours + 15 min reading

Questions

8

Pages

8

Answers included

No, questions only

Paper pattern

• Section A

  40 marks

  Compulsory: Question 1 has twenty one-mark multiple-choice items; Question 2 has ten two-mark short-answer and output questions

• Section B

  60 marks

  Questions 3–8, attempt any four; each asks for a Java program

Topics covered

• OOP concepts
• Operators and expressions
• Scanner class and packages
• Conditional statements and switch fall-through
• Loops
• Methods, pure methods and static methods
• Type casting, wrapper classes and boxing
• Types of errors
• Character and String methods
• Arrays, bubble sort and linear search
• Function overloading

Questions from this paper

1. The absence of which statement leads to a fall-through situation in a switch case statement?
2. Convert the do-while loop int x = 10; do { x--; System.out.print(x); } while (x >= 1); into a for loop.
3. Define a class to accept 10 characters from a user, arrange them in ascending order using the bubble sort technique, and display both the sorted and the original array.
4. A lead number is one whose sum of even digits equals its sum of odd digits, as in 3669. Overload print() so that print(int n) checks whether n is a lead number.
5. Define a class to accept a String and print the number of digits, alphabets and special characters in it (for example, "KAPILDEV@83").
6. Define a class to accept 20 values into an array of double type and search for a value using linear search, displaying "Found" with its position or "not found".